This page is largely here just for reference; it's simple
plug'n'chug calculation using similar triangles, and there's not much
exciting or surprising in the results. (I'll mention some
examples of each configuration as I go to try to add a little
interest...)
We'll consider the real
and/or virtual images formed from a scene by ideal positive and
negative lenses, and by ideal positive and negative mirrors in turn.
We'll also consider the images formed by lenses when a real image
is "projected through" them, so that the "scene" is "behind" the
lens.
In each case, we'll be using the properties we described for
ideal lenses and mirrors. In particular, we will be
assuming
that an image is formed in each case. The derivations done here
are just to pin down the location and size of the image, which we can
do by tracing two rays to one point on the image in each case; from
that, plus the
assumption that an image will be formed, we can
obtain all the information we need. In the figures, the "scene"
consists of a simple vertical arrow, and it's located to the right of
the illustration. For lenses, the viewer (or "eyepoint") is
somewhere off to the left, unless we mention otherwise. For mirrors, the viewer is located
to the right.
Throughout the page, we're going to use the following labels on the diagrams:
1. Positive Lens, Scene in Front of Lens, Beyond Focus (inverted real image)
(Also see properties of an
ideal positive lens.) The "scene" (a simple arrow) is to the right of the lens, with an image formed on the left side of the lens (
figure 1).
(This is the behavior of the front ("objective") lens in
binoculars, simple refractor telescopes, microscopes, and simple
camera lenses.)
l1 is the distance from the lens to the scene, and
l2
is the distance to the image formed by the lens. The
magnification is defined as the ratio of the image size to the scene
size:
(1a)
There are a number of useful formulas for the magnification, which we'll now extract from the figure.
The
green ray passes through the center of the lens and is not bent. Comparing the triangles marked with green arcs, we see
(1b)
The
blue ray passes through the right focus, and hence will be
bent to exit parallel to the axis. Comparing the triangles marked with
blue arcs, we see
(1c)
Finally, the
red
ray in figure 1 enters from the right going parallel to the axis, so it
will be bent to pass through the left focus. Comparing the similar
triangles marked with red arcs, we also see
(1d)
Finally, the angles subtended by the scene and the image, as viewed from the center of the lens, are
identical, as we can see by looking at the green ray. This is a common feature of all the images formed by lenses and mirrors.
When the scene is at infinity (
l1 = infinity), the image is formed at the left focus of the lens (
l2 =
f).
The angles subtended by the scene and the image are equal when
viewed from the center of the lens, as we can see from the two angles
marked with green arcs in figure 1. Hence the
size of the image in this case is:
(1e)
For small angles, which is all we're typically dealing with in a telescope, this is almost exactly
(1f)
Figure 1: Real image formed by a positive lens
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2. Positive Lens, Scene in Front of Lens, Within Focus (erect virtual image)
The scene (a simple arrow, again) is to the right of the lens, but closer to the lens than the right focus (
figure 2). A virtual image is formed to the
right
of the scene; it must be viewed by looking through the lens from the
left. (This is the configuration of a simple magnifying glass or
loupe. It's also how mild "reading glasses" work. The
eyepiece on a simple astronomical telescope is also configured this
way. Because the primary lens on a telescope projects an
inverted
image, and the eyepiece doesn't invert it "back", when we look through
an astronomical telescope the image we see is inverted.) The
actual light rays are shown as
solid
colored lines. The "apparent paths" of the rays from the head of
the arrow in the scene are traced back to where they meet at the head
of the arrow in the image. The paths which are traced back are
shown as dotted lines.
The magnification is once again defined to be
(2a)
Looking at the green ray which passes through the center of the lens in
figure 2,
both the scene and the image lie in the triangle marked with a green
arc which is formed by the green ray and the green dotted line "traced
back" to the image. Comparing the similar triangles they form, we see
(2b)
From
the triangle marked with a red arc, whose top is formed by the red ray
from the head of the scene arrow and the dotted line traced back to the
right focus, we can see
(2c)
Finally, inspecting the triangle marked with a blue arc, we can see that
(2d)
When the scene is on the focus (
l1 =
f),
the magnification is infinite, but the image is pushed out to infinity;
it still subtends the same angle as the scene, when they're both viewed
from the center of the lens.
Figure 2: Virtual image formed by a positive lens
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3. Positive Lens, Scene Behind Lens (erect real image)
The "real scene" is actually someplace off to the right of the diagram in
figure 3.
An image of it, which we call the "projected scene", is generated
by an optical system of some sort, and projected from right to left,
through
the lens. (This configuration is used in the front lens of a
simple teleconverter or Barlow lens. It's also how the lenses of
your eyes are operating if you look at a distant object through glasses
for farsightedness; in that case the lenses of the glasses are actually
projecting images
through the lenses of your eyes.)
If
we removed the lens, the scene would appear as shown at the left of
figure 3. With the lens there, however, it's shifted and scaled;
to find out how we trace the rays which
would have gone to the head of the projected scene arrow. The actual light rays are shown as solid lines. The paths they
would have followed are shown as dotted lines leading to the head of the scene arrow.
Again, we define the magnification,
(3a)
By inspecting the triangle marked with a green arc, we can see that
(3b)
From the blue triangle, we can see that
(3c)
And finally, from the triangle with the red arc, we can see that
(3d)
When
the projected scene is infinitely distant (off to the left), all rays
leading to a particular point on it are parallel, and the situation is
identical to the case where the
real scene is infinitely distant, but off to the
right (and inverted).
Figure 3: Positive lens forming real image from scene projected through the lens
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4. Negative Lens, Scene in Front of Lens (erect virtual image)
(Also see properties of an
ideal negative lens.) In
figure 4,
we've shown the scene on the right, and the (virtual) image is formed
between the right focus and the lens. (This is the arrangement of the lenses in glasses for nearsightedness.)
This is actually described nicely by
case (1) with a
negative
focal length for the lens. None the less, in this section we'll find
the formulas for use when all values are given as lengths (and are treated as
positive or zero).
The actual rays are shown
as solid lines. We've traced the the paths "back to the image"
with dotted lines, and the lines leading to the foci are also shown
with dotted lines.
Again we define
(4a)
and by inspecting the green ray we again see that
(4b)
From the triangle formed by the blue ray, we see that
(4c)
And from the triangle formed by the red ray, we see
(4d)
These were all identical to the equivalent formulas for
case (3), a positive lens forming a real image from an image projected
through
the lens. The geometry of the two cases is identical, though of
course the paths followed by the light rays are somewhat different.
When the scene is infinitely distant, the image is formed on the focus of the lens (
l2 =
f).
Again, the angles subtended by the image and the scene are equal,
as viewed from the center of the lens. Consequently, if the angle
subtended by the image is
θ, we again have the image size as:
(4e)
Figure 4: Negative lens forming virtual image
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5. Negative Lens, Scene Behind Lens, Beyond Focus (inverted virtual image)
As with
case (3), in
figure 5 we're projecting the scene
through
the lens. If the lens were not there, the scene would appear at
the left, as shown by the "(Projected) Scene" in the figure.
However, the lens blocks the light coming in from the right, and
forms an inverted virtual image in place of the real image. (This
is the configuration used in the eyepieces of simple opera glasses,
where the projected image is formed by a positive lens in front.)
This arrangement is also covered by
case (3) with a
negative
focal length and a projected scene. In this section, however,
we'll derive the formulas for use when all values are lengths, given as
positive or zero.
Solid lines indicate light rays, while dotted ones show the paths the rays
would have taken had the lens not been present. Dotted lines are also used to "backtrack" rays to the location of the virtual image.
As always, we have
(5a)
and checking the green ray shows that
(5b)
From the triangles marked with blue arcs, we can see that
(5c)
And from the triangles marked with red arcs, we see
(5d)
These formulas are identical to the ones from
case (1),
a positive lens forming a real image. The geometry is identical,
too, save that the diagrams are flipped relative to each other.
When
the projected scene is on the focus of the lens, the virtual image is
at infinity, and subtends the same angle as the scene, as viewed from
the center of the lens.
Figure 5: Negative lens, scene behind lens, forming inverted virtual image
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6. Negative Lens, Scene Behind Lens, Within Focus (erect real image)
This is the same as
case (5), save that we've moved the scene closer to the lens, so that it's between the lens and the rear focus (
figure 6).
(This configuration is used on the rear lens of a simple
teleconverter or Barlow lens, where the scene is projected through the
lens by a positive lens placed in front.)
This case is actually identical to
case (2) with a
negative focal length, and a direct image (not projected).
The magnification is:
(6a)
From the triangle marked with a green arc, we also have:
(6b)
From the red ray, which forms the triangle marked with the red arc, we have
(6c)
From the blue ray, which forms the triangle marked with a blue arc, we see
(6d)
Figure 6: Negative lens, scene behind lens, forming erect real image
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A mirror's behavior is identical with that of a lens, save that
everything is reflected. Figures 1 through 6 describe the behavior if
we just
fold
them in the middle, along the line marked "lens".
Because of that, and because making these diagrams takes quite a
bit
of time, we're not going to provide illustrations for the mirror cases;
we'll refer to the diagrams we used for the lenses and just repeat the
resulting formulas.
There are six more cases for mirrors -- the same six cases we already treated for lenses, but reflected. We'll define
m,
h,
l, and
f the same way we
defined them for lenses.
7. Positive (Concave) Mirror, Scene in front, beyond focus (inverted real image)
See
figure 1 (but fold it over along the "lens" line), and see the discussion for
case (1).
This is the arrangement used in the primary mirror of a
telescope, as well as the primary mirror of a mirror telephoto lens for
a camera. We repeat the results of
case (1) here with no further comment:
(7a)
(7b)
(7c)
(7d)
The formula for image size is very important for telescopes. When the scene lies at infinity and subtends angle
θ, the image size will be:
(7e)
8. Positive Mirror, Scene in front, within focus (erect virtual image)
See
figure 2 (but fold it along the line marked "lens"), and see the discussion for
case (2). Note that the virtual image appears
behind the mirror -- you must look into the mirror to see it.
A
positive mirror with the scene closer to the mirror than the focal
length is a "magnifying mirror"; it's how makeup mirrors are
configured. Here are the results from
case (2), repeated:
(8a)
(8b)
(8c)
(8d)
9. Positive Mirror, Scene behind mirror (erect real image)
By "scene
behind
the mirror", we mean a real image is projected by an optical system of
some sort, and a mirror is interposed in the path. If the mirror
weren't there, the scene would appear
behind the mirror's actual position. I can't think of a common example which uses a positive mirror in this arrangement.
See
figure 3, and imagine it folded along the "lens" line, and see the discussion of
case (3). Results, copied from case 3:
(9a)
(9b)
(9c)
(9d)
10. Negative (concave) Mirror, Scene in front (erect virtual image)
See
figure 4, but fold it along the "lens" line, and see the discussion for
case (4). But note that the virtual image appears
behind the mirror -- you must look into the mirror to see it.
Examples
of this configuration abound. Christmas tree balls, those shiny
spheres people put in their gardens, the bumpers of old cars -- just
about any mirrored surface that's wrapped around something will provide
an example of this.
Results from
case (4), copied:
(10a)
(10b)
(10c)
(10d)
The size of the image of a distant object, reflected in such a mirror, will be:
(10e)
11. Negative Mirror, Scene behind mirror, beyond focus (inverted virtual image)
See
figure 5, folded along the "lens" line, and see the discussion of
case (5). Again keep in mind that, when we say "scene
behind
the mirror", we mean the scene is projected to a spot that would lie
behind the mirror, if the mirror weren't there. The distance from the
mirror's location to the plane of the projected scene would be
longer than the focal length of the mirror.
Note that the virtual image appears
behind the mirror -- you must look into the mirror to see it. I can't think of a common example of this arrangement (but see
case (12) for a related arrangement which is widely used).
Results, copied from
case (5):
(5a)
(5b)
(5c)
(5d)
12. Negative Mirror, Scene behind mirror, within focus (erect real image)
See
figure 6, folded along the line marked "lens", and see the discussion of
case (6).
Again, the scene is projected along a path which would form an
image behind the location of the mirror, if the mirror were not there.
In this case, the projected scene would lie no farther from the
mirror's position than
f.
This configuration is used in
the secondary mirror of some telescopes. By using a short focal
length primary and a negative secondary, it's possible to build a
compact telescope with the same optical properties as a far larger
Newtonian reflector. (But such scopes typically don't use
parabolic mirrors. They generally combine a "corrector plate" -- a
thin front lens -- with either spherical or hyperbolic surfaces on the
mirrors. That's way beyond the 'scope' of this page, however.)
Results, copied from
case (6):
(6a)
(6b)
(6c)
(6d)
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created on 09/18/2007